Jharkhand Staff Selection Commission has successfully conducted the exam for 3120 PGT Teacher Vacancies from 18th August to 10th September, 2023. Candidates appearing for the JSSC PGT exam can use the answer key to check their answers and gauge how well they have performed in the exam. . Candidates who have appeared in the exam and are currently expecting the release of JSSC PGT Answer Key 2023 2nd week of September 2023 https://jssc.nic.in/.
JSSC PGT Answer Key 2023
Jharkhand Staff Selection Commission (JSSC) Post Graduate Trained (PGT) Exam is a highly anticipated event for those interested in securing teaching posts in the state of Jharkhand, India. The JSSC PGT exam evaluates the knowledge and skills of the candidates in their chosen subjects and JSSC PGT Answer Key 2023 release is of vital importance in the examination process.
JSSC PGT Exam is a competitive exam successfully conducted from 18th August 2023 to 10th September 2023 for the recruitment of eligible candidates for Post Graduate Trained Teacher Posts in various subjects. It covers a wide range of subjects including Mathematics, English, History, Physics, Chemistry and more. The examination is usually conducted in multiple stages, including a written test followed by an interview or document verification process. Aspiring teachers who have completed their Masters in the relevant subject are eligible to appear in the examination.
jssc.nic.in PGT Answer Key 2023 Download Link
JSSC PGT Answer Key 2023 is very significant as it provides applicants with a rough assessment of their performance. Before the release of the official results, candidates can use the JSSC PGT Answer Key 2023 as a reference to evaluate their responses and determine their likely score. Candidates can compare their answers with the correct answers given by the commission, giving them a clear idea of how well they have done.
|Test Name||JSSC PGT Exam 2023|
|Date of Examination||18 August to 10 September 2023|
|Condocting body||Jharkhand Staff Selection Commission|
|Answer Key Release Date||Second week of September 2023|
|Objection window date||Second to third week of September 2023|
|Date of Result||October 2023|
How to Download Jharkhand PGT Answer Key 2023?
JSSC PGT Answer Key 2023 is usually released by Jharkhand Staff Selection Commission on its official website. Candidates can access the answer key by following these steps:
- Visit Official Website: Visit the official website of Jharkhand Staff Selection Commission (JSSC) – www.jssc.nic.in.
- Find Answer Key Section: Look for “Answer Key” or “Notice Board” section on the website. This section usually contains information about various ongoing and recently conducted tests.
- Select the relevant Exam: JSSC PGT Answer Key 2023 link and click on it. Make sure you choose the correct subject and question paper code.
- Download Answer Key: The answer key is available in a PDF format. You can download and save the document for reference.
Raise objection against JSSC PGT Answer Key 2023
Once candidates access the JSSC PGT Answer Key 2023, they can compare their answers with the answers provided in the key. For each question, candidates have to check whether their chosen option matches the correct answer. They should tally the total correct and incorrect responses to estimate their provisional score.
In some cases, candidates may face discrepancy or disagreement with the answers given in the official answer key. JSSC will provide a window of opportunity for candidates to raise objections or challenges regarding the answer key between the second to third week of September 2023.
How to Calculate Marks for Jharkhand PGT Exam 2023?
The Preliminary Examination is an objective type written examination with a total of 150 questions to be answered within 2 hours. Each question carries 3 marks, resulting in a total of 450 marks for the exam. Here is how you will calculate the marks for the preliminary exam:
- Correct Answer: +3 Marks
- Wrong answer: -1 mark
- Unanswered Questions: 0 Marks
Formula for Calculation of Preliminary Exam Score:
Total Score = (3 * Number of Correct Answers) – (1 * Number of Wrong Answers)
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